Philosophy210-
Logical Thought
Review Exercises
Possible Answers
Translations:
(1) E: j is earlier than k P: j is part of k
H: j
has k
on it at time [1] T: at
time j,
k
tastes better than l
B: j
is a hamburger c:
the universal glob of catsup
"x"y"t [(Bx Ù By Ù – $z [Pzc Ù (Hxzt Ú Hyzt)] Ù –Ttxy Ù –Ttyx) ®
"t1 [($w(Pwc Ù Hxwt1) Ù–$u(Puc Ù Hyut1))] ® Tt1xy]]
That was quite hard. It would be nearly as good to treat the
taste as a thing, and then to say that the taste of x at t1 is better than the taste of x at t. That way you
only need one burger. But what you must not
say is that any burger with catsup tastes better than any without. (Supply your
own counterexample.)
(2) S: j is a shirt C:
j
is a collar
P: j
is part of k O:
j
is on k
R: j
is shaped into a ring H:
j
has k
j: John d:
the universal glob of dirt
$x(Sx Ù Hjx Ù $y(Cy ÙHxy Ù $z[Pzd Ù RzÙ Ozy]))
(3) S: j has seen k T: j is
troublesome
K: j
knows k j:
Jesus
i: the speaker of the sentence
"x[(Tx Ù Six) ® (Kjx Ù "y( y≠j ® –Kyx))]
Here we cannot use an operator for 'know'. The knowledge is not knowledge that something is the case, but acquaintance of a thing. It is the difference between 'I
know Henry' (knowledge by acquaintance) and 'I know that Henry is a creep'(knowledge
that).
(4) P: j is the president of k B2,1: at time j, k believes that [1]
G: j
is guilty S:
j
is shot at time k
E: j
is earlier than k c:
Chile
$y(Pyc Ù "x"t ( B2,1 t y Gx ® $t1( Ett1 Ù Sxt1)))
(5) N: j needs k N1,1: j needs it to be the case that [1]
H: j
has k i:
the speaker of the sentence
o: the person addressed
(a) Nio
(b) N1,1i Noi Note
that both (a) and (c) require a propositional
(c) N1,1 $x Hix sense
of needing, not just a relational sense.
(6) E: j is an egg B:
j
is boiled
B2: j belongs to k P2: j is part of k
P3: j puts k on l P:
j
is a sweet potato
j: Jessica a:
the universal glob of applesauce
$x[ Sx Ù B2xj Ù $y(By Ù EyÙ B2yj Ù $< $z (P2za Ù P3jzx) Ù "<–$w (P2wa Ù P3jwy)]
(7) W1,1: j wants it to be the case that [1] B: j buys k
D1,1: j decides whether [1] W: j works in k
S0,1: it should be the case that [1] A:
j
assigns k
H1,1: j hopes it to be the case that [1] B: j is a book
l: the library indicated h:
the teacher indicated
$x[ Bx Ù $< H1,1h Ahx Ù –$y $< W1,1y D1,1 y S0,1 $z( Wzl ÙBzx)]
The last clause is done that way because the library itself can't literally buy anything. Only a
person can. But that is not quite right either, because a person who works for
the library (or especially in the library)
can buy a book that the library doesn't buy. This is a problem with no easy
solution. If you saw the problem, then you did well.